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Interactive practice · A-Level Maths
Work through exam-style solutions one line at a time. At each step, choose the line you think comes next, some of the wrong options are exactly what you'd write after a slip earlier on. Press Mark to see which steps you got right and why the others are wrong. This is practice, not a study guide: do it actively.
Stuck on a step?
If the same kind of slip keeps costing you method and accuracy marks, a few focused sessions fix it fast. One-to-one online A-Level Maths and Further Maths tuition, matched to your exam board.
Every question below is fully interactive above: open it, build the solution line by line, and be marked against an authentic OCR-style mark scheme with per-line feedback. The stems are listed here in full.
Chain rule: \(\frac{dy}{dx}=4(2x^{3}-5)^{3}\times 6x^{2}\) (M1) \(=\) \(24x^{2}(2x^{3}-5)^{3}\) (A1). Total: 2 marks.
\(\int_{1}^{3}(3x^{2}-4x+1)\,dx=[\,x^{3}-2x^{2}+x\,]_{1}^{3}\) (M1 A1) \(=(27-18+3)-(1-2+1)\) (dM1) \(=12-0=\) 12 (A1). Total: 4 marks.
With \(u=x^{3}+2,\ du=3x^{2}\,dx\) (M1), the integral becomes \(\int u^{4}\,du\) (M1) \(=\dfrac{u^{5}}{5}+c\) (A1) \(=\) \(\dfrac{(x^{3}+2)^{5}}{5}+c\) (A1). Total: 4 marks.
\((3+2x)^{4}=3^{4}+\binom{4}{1}3^{3}(2x)+\binom{4}{2}3^{2}(2x)^{2}+\dots\) (M1) \(=\) \(81+216x+216x^{2}\) (A1, A1). Total: 3 marks.
\(\log_{2}[x(x-2)]=3\) (M1) \(\Rightarrow x(x-2)=2^{3}=8\) (M1) \(\Rightarrow x^{2}-2x-8=0\Rightarrow(x-4)(x+2)=0\) (A1). Reject \(x=-2\): \(x=4\) (A1). Total: 4 marks.
\((2\cos x+1)(\cos x-1)=0\) (M1) \(\Rightarrow\cos x=-\tfrac12\) or \(1\) (A1). So \(x=120^{\circ},240^{\circ}\) (A1) and \(x=0^{\circ}\) (A1). \(x=0^{\circ},120^{\circ},240^{\circ}\). Total: 4 marks.
(a) \(|\mathbf{a}|=\sqrt{5^{2}+(-12)^{2}}\) (M1) \(=\sqrt{169}=\) 13 (A1).
(b) Unit vector \(=\dfrac{\mathbf{a}}{|\mathbf{a}|}=\) \(\tfrac{1}{13}(5\mathbf{i}-12\mathbf{j})\) (A1). Total: 3 marks.
Let the numbers be \(2n+1\) and \(2n+3\) (B1). Then \((2n+1)+(2n+3)=4n+4=4(n+1)\), which is a multiple of 4 (B1). Proven. Total: 2 marks.
\(P(X=3)=\binom{12}{3}(0.25)^{3}(0.75)^{9}=220\times0.015625\times0.0750847\approx\) 0.2581 (4 d.p.) (M1 A1). Total: 2 marks.
(a) Smooth floor, so \(F=ma\Rightarrow 10=4a\) (M1) \(\Rightarrow a=\) \(2.5\ \text{m s}^{-2}\) (A1).
(b) From rest, \(v=u+at=0+2.5\times3=\) \(7.5\ \text{m s}^{-1}\) (A1). Total: 3 marks.
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